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(D) The time $t$ required for the thickness of an ice layer to increase from $y_1$ to $y_2$ is given by the formula: $t = \frac{ho L}{2K	heta} (y_2

Vedclass · Accepted Answer

$21$

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(D) The time $t$ required for the thickness of an ice layer to increase from $y_1$ to $y_2$ is given by the formula: $t = \frac{ho L}{2K	heta} (y_2^2 - y_1^2)$.For the first layer ($0 \, cm$ to $1 \, cm$):$t_1 = C(1^2 - 0^2) = C(1) = 7 \, h$,where $C = \frac{ho L}{2K	heta}$.For the second layer ($1 \, cm$ to $2 \, cm$):$t_2 = C(2^2 - 1^2) = C(4 - 1) = 3C$.Since $C = 7 \, h$,we have:$t_2 = 3 	imes 7 = 21 \, h$.

If it takes $7 \, h$ to form a $1 \, cm$ thick layer of ice on a pond at $0^o C$,how many hours will it take for the thickness of the ice layer to increase from $1 \, cm$ to $2 \, cm$?

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