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(C) For an isobaric process, the heat energy supplied is given by the formula: $(\Delta Q)_p = \mu C_p \Delta T$.Since $H_2$ is a diatomic gas, its mo

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$1050$

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(C) For an isobaric process, the heat energy supplied is given by the formula: $(\Delta Q)_p = \mu C_p \Delta T$.Since $H_2$ is a diatomic gas, its molar heat capacity at constant pressure is $C_p = \frac{7}{2}R$.Given: $\mu = 5 \, 	ext{moles}$, $\Delta T = 60^{\circ}C - 30^{\circ}C = 30 \, K$, and $R = 2 \, 	ext{cal/mol} \cdot K$.Substituting the values: $(\Delta Q)_p = 5 	imes (\frac{7}{2} 	imes 2) 	imes 30$.$(\Delta Q)_p = 5 	imes 7 	imes 30 = 1050 \, 	ext{calories}$.

The energy required to raise the temperature of $5 \, \text{moles}$ of $H_2$ gas from $30^{\circ}C$ to $60^{\circ}C$ at constant pressure is ......... $\text{calories}$ $(R = 2 \, \text{cal/mol} \cdot \text{K})$.

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