(C) Using the ideal gas law,$PV = \mu RT$,we have the relation $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.Given: $T_1 = 27^{\circ}C = 27 + 273 = 300

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(C) Using the ideal gas law,$PV = \mu RT$,we have the relation $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.Given: $T_1 = 27^{\circ}C = 27 + 273 = 300 \ K$,$P_2 = 2P_1$,and $V_2 = 3V_1$.Substituting these values into the equation:$\frac{P_1 V_1}{T_1} = \frac{(2P_1)(3V_1)}{T_2}$$\frac{1}{T_1} = \frac{6}{T_2}$$T_2 = 6T_1 = 6 \times 300 = 1800 \ K$.To convert the temperature to Celsius: $T(^{\circ}C) = 1800 - 273 = 1527^{\circ}C$.

Class 11 Physics Kinetic Theory of Gases Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

Medium

$A$ gas at a temperature of $27^{\circ}C$ has a volume $V$ and pressure $P$. If the pressure is doubled and the volume is tripled,what will be the new temperature in $^{\circ}C$?

A
$1800$
B
$162$
C
$1527$
D
$600$

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Class 11 Questions

Class 11

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Chapter

Kinetic Theory of Gases

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Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

At constant pressure,the ratio of the increase in volume of an ideal gas per degree rise in temperature to its original volume is ... (where $T$ is the absolute temperature of the gas).

Easy

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The gas equation $\frac{PV}{T} = \text{constant}$ is true for a constant mass of an ideal gas undergoing:

Medium

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At $10^{\circ} C$,the value of the density of a fixed mass of an ideal gas divided by its pressure is $x$. At $110^{\circ} C$,this ratio is:

MediumAIPMT 2008

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The volume versus temperature graph for a fixed amount of gas at constant pressures $P_1$ and $P_2$ is shown in the figure. From this,it can be concluded that...........

Medium

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$A$ gas is heated through $1\,^{\circ}C$ in a closed vessel. Its pressure is increased by $0.5\%$. The initial temperature of the gas is ...... $^{\circ}C$.

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$A$ gas at a temperature of $27^{\circ}C$ has a volume $V$ and pressure $P$. If the pressure is doubled and the volume is tripled,what will be the new temperature in $^{\circ}C$?

Similar Questions

At constant pressure,the ratio of the increase in volume of an ideal gas per degree rise in temperature to its original volume is ... (where $T$ is the absolute temperature of the gas).

The gas equation $\frac{PV}{T} = \text{constant}$ is true for a constant mass of an ideal gas undergoing:

At $10^{\circ} C$,the value of the density of a fixed mass of an ideal gas divided by its pressure is $x$. At $110^{\circ} C$,this ratio is:

The volume versus temperature graph for a fixed amount of gas at constant pressures $P_1$ and $P_2$ is shown in the figure. From this,it can be concluded that...........

$A$ gas is heated through $1\,^{\circ}C$ in a closed vessel. Its pressure is increased by $0.5\%$. The initial temperature of the gas is ...... $^{\circ}C$.

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