A ball of mass 1 kg moving with a velocity o | vedclass

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(C) Let the initial momentum be $\vec{p}_i = m_1 v_1 = 1 	imes 0.4 = 0.4 \ kg \cdot m/s$ along the x-axis.After collision,the first ball moves along

Vedclass · Accepted Answer

$0.5$

Vedclass · Answer

(C) Let the initial momentum be $\vec{p}_i = m_1 v_1 = 1 	imes 0.4 = 0.4 \ kg \cdot m/s$ along the x-axis.After collision,the first ball moves along the y-axis with momentum $p_{1f} = 1 	imes 0.3 = 0.3 \ kg \cdot m/s$.Let the momentum of the second ball be $\vec{P} = P_x \hat{i} + P_y \hat{j}$.By conservation of linear momentum along the x-axis:$p_{ix} = p_{1fx} + P_x \implies 0.4 = 0 + P_x \implies P_x = 0.4 \ kg \cdot m/s$.By conservation of linear momentum along the y-axis:$p_{iy} = p_{1fy} + P_y \implies 0 = 0.3 + P_y \implies P_y = -0.3 \ kg \cdot m/s$.The magnitude of the momentum of the second ball is:$P = \sqrt{P_x^2 + P_y^2} = \sqrt{(0.4)^2 + (-0.3)^2} = \sqrt{0.16 + 0.09} = \sqrt{0.25} = 0.5 \ kg \cdot m/s$.

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