If two vertices of an equilateral triangle are $(1, 0)$ and $(3, 0)$,and the third vertex lies in the first quadrant,find the area of the triangle.
- A$\frac{\sqrt{3}}{4}$
- B$\frac{\sqrt{3}}{2}$
- C$\sqrt{3}$
- D$\text{None of these}$
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