If three points P, Q, R on the parabola y^2 = | vedclass

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(B) Let the coordinates of $P, Q, R$ be $(at_i^2, 2at_i)$ for $i = 1, 2, 3$. Since the ordinates $2at_1, 2at_2, 2at_3$ are in geometric progression,$t

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$A$ line passing through $Q$ parallel to the $y$-axis.

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(B) Let the coordinates of $P, Q, R$ be $(at_i^2, 2at_i)$ for $i = 1, 2, 3$. Since the ordinates $2at_1, 2at_2, 2at_3$ are in geometric progression,$t_1, t_2, t_3$ are also in geometric progression. Thus,$t_1 t_3 = t_2^2$. The equations of the tangents at $P$ and $R$ are $t_1y = x + at_1^2$ and $t_3y = x + at_3^2$. Solving these,the intersection point $(x, y)$ satisfies $x = at_1t_3 = at_2^2$. Since the $x$-coordinate of the intersection is $at_2^2$,which is the $x$-coordinate of $Q$,the intersection point lies on a line passing through $Q$ parallel to the $y$-axis.

If three points $P, Q, R$ on the parabola $y^2 = 4ax$ are such that their ordinates are in geometric progression,then the tangents at $P$ and $R$ intersect on:

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