The length of the perpendicular from the origin to a line is $4$ units,and the perpendicular makes an angle of $30^{\circ}$ with the positive direction of the $x$-axis. Find the equation of the line.

  • A
    $2x + 3y = 9$
  • B
    $\sqrt{3}x + y = 8$
  • C
    $x + 2y = 3$
  • D
    None of these

Explore More

Similar Questions

The equation of a line,whose perpendicular distance from the origin is $7$ units and the angle,which the perpendicular to the line from the origin makes,is $120^{\circ}$ with the positive $X$-axis,is

$A$ straight line through the point $P(1, 2)$ makes an angle $\theta$ with the positive $X$-axis in the anticlockwise direction and meets the line $x + \sqrt{3}y - 2\sqrt{3} = 0$ at $Q$. If $PQ = \frac{1}{2}$,then $\theta =$

The equation of the line passing through $(a \cos^3 \theta, a \sin^3 \theta)$ and parallel to the line $x \sec \theta + y \csc \theta = a$ is:

$A$ line meets the $x$-axis and $y$-axis at the points $A$ and $B$ respectively. If the midpoint of $AB$ is $(x_1, y_1)$,then the equation of the line is:

$A$ line $L$ through $A(-5,-4)$ meets the lines $x+3y+2=0$,$2x+y+4=0$,and $x-y-5=0$ at points $B$,$C$,and $D$ respectively. If $\left(\frac{15}{AB}\right)^2+\left(\frac{10}{AC}\right)^2=\left(\frac{6}{AD}\right)^2$,then find the equation of $L$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo