The $x$-intercept and $y$-intercept of the line $2x - 3y = 6$ are respectively:

The angles made with the $X$-axis by the two lines passing through the point $P(1, 2)$ and cutting the line $x+y=4$ at a distance $\frac{\sqrt{6}}{3}$ units from the point $P$ are

The points $A(-a, -b)$,$B(0, 0)$,$C(a, b)$,and $D(a^2, ab)$ are

The equations of the lines which make intercepts on the axes whose sum is $8$ and product is $15$ are

Find the equation of the line passing through the point $(-1, 2)$ and parallel to the line $3x - 4y + 5 = 0$.

The equation of the line,passing through the point $(a \cos^3 \theta, a \sin^3 \theta)$ and perpendicular to the line $x \cos \theta - y \sin \theta = a$,is