Find the equation of the line that bisects th | vedclass

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(C) The slope of the line is $m = 	an(45^{\circ}) = 1$.The midpoint of the line segment joining $(5, 3)$ and $(4, 4)$ is given by:$M = \left( \frac{5

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$x - y - 1 = 0$

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(C) The slope of the line is $m = 	an(45^{\circ}) = 1$.The midpoint of the line segment joining $(5, 3)$ and $(4, 4)$ is given by:$M = \left( \frac{5+4}{2}, \frac{3+4}{2} ight) = \left( \frac{9}{2}, \frac{7}{2} ight)$.The equation of the line passing through $(x_1, y_1) = \left( \frac{9}{2}, \frac{7}{2} ight)$ with slope $m = 1$ is:$y - y_1 = m(x - x_1)$$y - \frac{7}{2} = 1 \left( x - \frac{9}{2} ight)$$y - \frac{7}{2} = x - \frac{9}{2}$$x - y - \frac{9}{2} + \frac{7}{2} = 0$$x - y - 1 = 0$.

Find the equation of the line that bisects the line segment joining the points $(5, 3)$ and $(4, 4)$ and makes an angle of $45^{\circ}$ with the positive direction of the $x$-axis.

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