If the vertex of a parabola is (2, 0) and the | vedclass

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(D) The axis of the parabola is the line passing through the vertex and perpendicular to the directrix. Since the directrix is the $y$-axis $(x = 0)$,

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$(4, 0)$

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(D) The axis of the parabola is the line passing through the vertex and perpendicular to the directrix. Since the directrix is the $y$-axis $(x = 0)$,the axis of the parabola is the $x$-axis.Let the focus be $S(a, 0)$.The vertex is the midpoint of the segment joining the focus and the point of intersection of the axis and the directrix.The point of intersection of the axis ($x$-axis) and the directrix ($y$-axis) is $Z(0, 0)$.Since the vertex $(2, 0)$ is the midpoint of $ZS$,we have:$\frac{a + 0}{2} = 2 \implies a = 4$.Thus,the focus is $(4, 0)$.

If the vertex of a parabola is $(2, 0)$ and the $y$-axis is its directrix,find its focus.

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