The theoretical value of the magnetic moment | vedclass

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(B) The complex formed by $Fe^{3+}$ and $CN^{-}$ is $[Fe(CN)_6]^{3-}$.In this complex,the oxidation state of $Fe$ is $+3$,which has an electronic conf

Vedclass · Accepted Answer

$1.73$

Vedclass · Answer

(B) The complex formed by $Fe^{3+}$ and $CN^{-}$ is $[Fe(CN)_6]^{3-}$.In this complex,the oxidation state of $Fe$ is $+3$,which has an electronic configuration of $[Ar] 3d^5$.$CN^{-}$ is a strong field ligand,which causes pairing of electrons in the $3d$ orbitals.For $d^5$ configuration with strong field ligand,the electrons are arranged as $t_{2g}^5 e_g^0$,resulting in $1$ unpaired electron $(n = 1)$.The magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ B.M.$Substituting $n = 1$,we get $\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ B.M.$

Column-$I$	Column-$II$
$(a) [Pt(NH_3)_3Cl]Br$	$(P) \text{Coordination isomerism}$
$(b) [Cr(NH_3)_5(NCS)]^{+2}$	$(Q) \text{Ionisation isomerism}$
$(c) [Co(H_2O)_6]Cl_3$	$(R) \text{Linkage isomerism}$
$(d) [PtCl_4][Pt(NH_3)_4]$	$(S) \text{Hydrate isomerism}$

The theoretical value of the magnetic moment of the complex formed by the reaction of $Fe^{3+}$ ion with $CN^{-}$ ligand is .......... $B.M.$

Similar Questions

$Fe^{2+}$ shows

Which of the following will show optical isomers?
$I$. $\text{cis}-[Co(NH_3)_2(en)_2]^{3+}$
$II$. $\text{trans}-[IrCl_2(C_2O_4)_2]^{3-}$
$III$. $[Rh(en)_3]^{3+}$
$IV$. $\text{cis}-[Ir(H_2O)_3Cl_3]$

Match the column:
Column-$I$ Column-$II$
$(a) [Pt(NH_3)_3Cl]Br$ $(P) \text{Coordination isomerism}$
$(b) [Cr(NH_3)_5(NCS)]^{+2}$ $(Q) \text{Ionisation isomerism}$
$(c) [Co(H_2O)_6]Cl_3$ $(R) \text{Linkage isomerism}$
$(d) [PtCl_4][Pt(NH_3)_4]$ $(S) \text{Hydrate isomerism}$

Which type of isomerism is exhibited by the isomers $[Co(NH_3)_5(SO_4)]Br$ and $[Co(NH_3)_5Br]SO_4$?

Which kind of isomerism is exhibited by the octahedral complex $Co(NH_3)_4Br_2Cl$?

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