The electronic configurations of Cr^{2+},Mn^{ | vedclass

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(D) The paramagnetic character depends on the number of unpaired electrons $(n)$.For $H_2O$ as a weak field ligand,the number of unpaired electrons in

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$[Co(H_2O)_6]^{2+}$

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(D) The paramagnetic character depends on the number of unpaired electrons $(n)$.For $H_2O$ as a weak field ligand,the number of unpaired electrons in these high-spin octahedral complexes are:$Cr^{2+} (d^4): t_{2g}^3 e_g^1, n = 4$$Mn^{2+} (d^5): t_{2g}^3 e_g^2, n = 5$$Fe^{2+} (d^6): t_{2g}^4 e_g^2, n = 4$$Co^{2+} (d^7): t_{2g}^5 e_g^2, n = 3$Since $[Co(H_2O)_6]^{2+}$ has the minimum number of unpaired electrons $(n = 3)$,it exhibits the minimum paramagnetic character.

List $I$ (Complex)	List $II$ (Type of isomerism)
$A$. $[Pt(NH_3)_2Cl_2]$	$I$. Optical
$B$. $[Co(en)_3]^{3+}$	$II$. Solvate
$C$. $[Co(NH_3)_5NO_2]Cl_2$	$III$. Geometrical
$D$. $[Cr(H_2O)_6]Cl_3$	$IV$. Linkage

The electronic configurations of $Cr^{2+}$,$Mn^{2+}$,$Fe^{2+}$,and $Co^{2+}$ ions are $d^4$,$d^5$,$d^6$,and $d^7$ respectively. Which of the following complexes has the minimum paramagnetic character?

Similar Questions

Which of the following square planar complex molecular formulas exhibits $cis-trans$ isomerism? ($a$ and $b$ are monodentate ligands)

Which of the following square-planar complexes exhibits $cis-trans$ isomerism?

The magnetic moment of the complexes is zero in:

Match List $I$ with List $II$ :
List $I$ (Complex) List $II$ (Type of isomerism)
$A$. $[Pt(NH_3)_2Cl_2]$ $I$. Optical
$B$. $[Co(en)_3]^{3+}$ $II$. Solvate
$C$. $[Co(NH_3)_5NO_2]Cl_2$ $III$. Geometrical
$D$. $[Cr(H_2O)_6]Cl_3$ $IV$. Linkage

Choose the correct answer from the options given below :

The magnetic moment (spin-only) of $[NiCl_4]^{2-}$ is ........ $B.M.$

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