How many ions are present in K_4[Fe(CN)_6]? | vedclass

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(D) The compound $K_4[Fe(CN)_6]$ is a coordination complex salt.Upon dissociation in an aqueous solution,it ionizes as follows:$K_4[Fe(CN)_6] \rightar

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(D) The compound $K_4[Fe(CN)_6]$ is a coordination complex salt.Upon dissociation in an aqueous solution,it ionizes as follows:$K_4[Fe(CN)_6] \rightarrow 4K^+ + [Fe(CN)_6]^{4-}$.There are $4$ potassium ions $(K^+)$ and $1$ complex ion $([Fe(CN)_6]^{4-})$.Therefore,the total number of ions produced is $4 + 1 = 5$.

How many ions are present in $K_4[Fe(CN)_6]$?

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