An aqueous solution of $1 \ mol$ of the coordination compound $[Co(NH_3)_5Cl_3]$ gives $3 \ mol$ of ions. If $1 \ mol$ of the same compound reacts with $2 \ mol$ of $AgNO_3$ to produce $2 \ mol$ of $AgCl_{(s)}$,what is the correct formula of the coordination compound?
- A$[Co(NH_3)_3Cl_3] \cdot 2NH_3$
- B$[Co(NH_3)_4Cl_2]Cl \cdot NH_3$
- C$[Co(NH_3)_4Cl]Cl_2 \cdot NH_3$
- D$[Co(NH_3)_5Cl]Cl_2$
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For the complexes $(A) \ CoCl_3 \cdot 6NH_3$,$(B) \ CoCl_3 \cdot 5NH_3$,and $(C) \ CoCl_3 \cdot 4NH_3$,if the secondary valency of $Co$ is $6$,what is its primary valency in each case?
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View SolutionWhen $1 \ mol$ of the complex $Co(NH_3)_5Cl_3$ is dissolved in water,it yields $3 \ mol$ of ions. When $1 \ mol$ of the same complex reacts with $2 \ mol$ of $AgNO_3$,it produces $2 \ mol$ of $AgCl_{(s)}$. What is the structure of this complex?
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