A 2 L solution is prepared by mixing 0.02 m | vedclass

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(A) The total volume of the mixture is $2 \ L$,containing $0.02 \ mol$ of each complex. Thus,$1 \ L$ of the mixture contains $0.01 \ mol$ of $[Co(NH_3

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$0.01, 0.01$

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(A) The total volume of the mixture is $2 \ L$,containing $0.02 \ mol$ of each complex. Thus,$1 \ L$ of the mixture contains $0.01 \ mol$ of $[Co(NH_3)_5SO_4]Br$ and $0.01 \ mol$ of $[Co(NH_3)_5Br]SO_4$.When $1 \ L$ of the mixture reacts with $AgNO_3$,only the ionizable $Br^-$ reacts: $[Co(NH_3)_5SO_4]Br + AgNO_3 	o [Co(NH_3)_5SO_4]NO_3 + AgBr(s)$. The moles of $AgBr$ $(Y)$ formed = $0.01 \ mol$.When $1 \ L$ of the mixture reacts with $BaCl_2$,only the ionizable $SO_4^{2-}$ reacts: $[Co(NH_3)_5Br]SO_4 + BaCl_2 	o [Co(NH_3)_5Br]Cl_2 + BaSO_4(s)$. The moles of $BaSO_4$ $(Z)$ formed = $0.01 \ mol$.

$A$ $2 \ L$ solution is prepared by mixing $0.02 \ mol$ of $[Co(NH_3)_5SO_4]Br$ and $0.02 \ mol$ of $[Co(NH_3)_5Br]SO_4$. If $1 \ L$ of this mixture $X$ is treated with $AgNO_3$ to give $Y$,and another $1 \ L$ of mixture $X$ is treated with $BaCl_2$ to give $Z$,find the moles of $Y$ and $Z$.

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