Considering the acidity of carboxylic acids:( | vedclass

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(D) The acidity of substituted benzoic acids is determined by the electronic effects of the substituents.$1$. The $-NO_2$ group is a strong electron-w

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$II > III > IV > I$

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(D) The acidity of substituted benzoic acids is determined by the electronic effects of the substituents.$1$. The $-NO_2$ group is a strong electron-withdrawing group ($-I$ and $-M$ effect).$2$. In $(II)$ $o-NO_2C_6H_4COOH$,the ortho effect significantly increases the acidity compared to other isomers.$3$. In $(III)$ $p-NO_2C_6H_4COOH$,the $-NO_2$ group exerts both $-I$ and $-M$ effects,making it more acidic than $(IV)$ $m-NO_2C_6H_4COOH$,where only the $-I$ effect operates.$4$. $(I)$ $PhCOOH$ has no electron-withdrawing group,so it is the least acidic.Therefore,the correct order of acidic strength is $(II) > (III) > (IV) > (I)$.

Considering the acidity of carboxylic acids:
$(I) PhCOOH$
$(II) o-NO_2C_6H_4COOH$
$(III) p-NO_2C_6H_4COOH$
$(IV) m-NO_2C_6H_4COOH$
What is the correct order of acidic strength?

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Considering the acidity of carboxylic acids:$(I) PhCOOH$$(II) o-NO_2C_6H_4COOH$$(III) p-NO_2C_6H_4COOH$$(IV) m-NO_2C_6H_4COOH$What is the correct order of acidic strength?