When R-CO-NH_2 is treated with Br_2 and KOH,i | vedclass

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Question

(A) The reaction described is the $Hofmann$ $Bromamide$ $Degradation$ reaction.In this reaction,the amide $(R-CO-NH_2)$ reacts with $Br_2$ in the pres

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$R-CO-NHBr$

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(A) The reaction described is the $Hofmann$ $Bromamide$ $Degradation$ reaction.In this reaction,the amide $(R-CO-NH_2)$ reacts with $Br_2$ in the presence of a strong base $(KOH)$ to form an isocyanate intermediate $(R-N=C=O)$.However,the initial step involves the formation of $N-bromamide$ $(R-CO-NHBr)$ by the replacement of a hydrogen atom on the nitrogen with a bromine atom.Thus,$R-CO-NHBr$ is the key intermediate formed during the process.

When $R-CO-NH_2$ is treated with $Br_2$ and $KOH$,it gives $R-NH_2$ as the major product. Which intermediate is involved in this reaction?

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