Which is the correct decreasing order of basi | vedclass

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(C) The basic strength of aromatic amines depends on the electron density on the nitrogen atom.Electron-donating groups (like $-CH_3$) increase the ba

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$IV > I > III > II$

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(C) The basic strength of aromatic amines depends on the electron density on the nitrogen atom.Electron-donating groups (like $-CH_3$) increase the basicity by increasing electron density on the nitrogen atom through the $+I$ effect.Electron-withdrawing groups (like $-NO_2$ and $-CN$) decrease the basicity by withdrawing electron density from the nitrogen atom through the $-M$ and $-I$ effects.Comparing the compounds:$(IV)$ $p$-Toluidine has a $-CH_3$ group ($+I$ effect),making it the most basic.$(I)$ Aniline has no substituent.$(III)$ $p$-Cyanoaniline has a $-CN$ group (strong $-M$ and $-I$ effect).$(II)$ $p$-Nitroaniline has a $-NO_2$ group (stronger $-M$ and $-I$ effect than $-CN$).Therefore,the decreasing order of basic strength is $(IV) > (I) > (III) > (II)$.

Which is the correct decreasing order of basic strength for the following compounds?
$(I)$ Aniline
$(II)$ $p$-Nitroaniline
$(III)$ $p$-Cyanoaniline
$(IV)$ $p$-Toluidine

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Which is the correct decreasing order of basic strength for the following compounds?$(I)$ Aniline$(II)$ $p$-Nitroaniline$(III)$ $p$-Cyanoaniline$(IV)$ $p$-Toluidine