What is the ratio of sigma (sigma) and pi (pi | vedclass

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(C) The chemical formula of toluene is $C_6H_5CH_3$.In the benzene ring,there are $6$ $C-C$ sigma bonds and $5$ $C-H$ sigma bonds.The side chain $CH_3

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$15 : 3$

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(C) The chemical formula of toluene is $C_6H_5CH_3$.In the benzene ring,there are $6$ $C-C$ sigma bonds and $5$ $C-H$ sigma bonds.The side chain $CH_3$ group has $1$ $C-C$ sigma bond and $3$ $C-H$ sigma bonds.Total sigma $(\sigma)$ bonds = $6 (	ext{ring } C-C) + 5 (	ext{ring } C-H) + 1 (	ext{side chain } C-C) + 3 (	ext{side chain } C-H) = 15$.There are $3$ pi $(\pi)$ bonds in the benzene ring.Therefore,the ratio of sigma $(\sigma)$ to pi $(\pi)$ bonds is $15 : 3$.

$I. -OH$	$II. -CN$
$III. -CO_2H$	$IV. -OCH_3$
$V. -NHCOCH_3$	$VI. -CHO$

What is the ratio of sigma $(\sigma)$ and pi $(\pi)$ bonds in toluene?

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