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(C) The acidity of phenols increases with the presence of electron-withdrawing groups $(EWG)$ like $-NO_2$ due to their $-I$ and $-M$ effects,which st

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$IV < I < II < III$

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(C) The acidity of phenols increases with the presence of electron-withdrawing groups $(EWG)$ like $-NO_2$ due to their $-I$ and $-M$ effects,which stabilize the phenoxide ion. Conversely,electron-donating groups $(EDG)$ like $-OH$ decrease acidity.$I$: $o$-Nitrophenol ($-NO_2$ at ortho position,$-I$ and $-M$ effect).$II$: $p$-Nitrophenol ($-NO_2$ at para position,$-I$ and $-M$ effect).$III$: $2,4,6$-Trinitrophenol (Picric acid,three $-NO_2$ groups,strongest acid).$IV$: Resorcinol ($m$-hydroxy phenol,$-OH$ group at meta position acts as an $EDG$ via $+M$ effect,making it the least acidic).Comparing $I$ and $II$: $p$-Nitrophenol $(II)$ is generally more acidic than $o$-Nitrophenol $(I)$ because $o$-Nitrophenol forms intramolecular hydrogen bonding,which stabilizes the molecule and makes the proton less available compared to $p$-Nitrophenol.Thus,the order of acidity (and $K_a$) is: $IV < I < II < III$.

What is the correct order of increasing dissociation constant $(K_a)$ for the following compounds?

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