Arrange the following carbanions in the decreasing order of their stability:
$(1) CH_3-CH_2^-, (2) CH_2=CH^-, (3) HC \equiv C^-$

What is the order of stability of carbon free radicals among ${3^\circ}$,${2^\circ}$,${1^\circ}$,and $\mathop C\limits^\bullet {H_3}$?

The correct order of stability for the following carbanions is:
$CH_2=CH^{-}, CH_3-CH_2^{-}, CH\equiv C^{-}$

Consider the following statements. Of these statements:
$(I) \ CH_3O-CH_2^+$ is more stable than $CH_3-CH_2^+$
$(II) \ Me_2CH^+$ is more stable than $CH_3-CH_2-CH_2^+$
$(III) \ CH_2=CH-CH_2^+$ is more stable than $CH_3-CH_2-CH_2^+$
$(IV) \ CH_2=CH^+$ is more stable than $CH_3-CH_2^+$

Which among the following carbocations has the maximum stability?

The bond dissociation energy of the $C-H$ bond for the compounds: $(I)\ CH_3-H, (II)\ CH_3-CH_2-H, (III)\ CH_2=CH-CH_2-H, (IV)\ C_6H_5-H$ follows the order: