Determine the IUPAC name of the given compoun | vedclass

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(D) The given structure is $CH_3-CH=CH-CH=CH-CH_3$. Numbering from either end gives the double bonds at positions $2$ and $4$. For the double bond at

Vedclass · Accepted Answer

$(2E, 4E)-hexa-2,4-diene$

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(D) The given structure is $CH_3-CH=CH-CH=CH-CH_3$. Numbering from either end gives the double bonds at positions $2$ and $4$. For the double bond at $C2$,the higher priority groups (the methyl group and the rest of the chain) are on opposite sides,which corresponds to the $E$ configuration. For the double bond at $C4$,the higher priority groups are also on opposite sides,which corresponds to the $E$ configuration. Therefore,the $IUPAC$ name is $(2E, 4E)-hexa-2,4-diene$.

Determine the $IUPAC$ name of the given compound.

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