Which of the following is the correct order o | vedclass

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(B) The acidic strength depends on the stability of the conjugate base formed after the loss of a proton $(H^+)$.$1$. $RCOOH$ (Carboxylic acid): The c

Vedclass · Accepted Answer

$RCOOH > HOH > ROH > HC \equiv CH$

Vedclass · Answer

(B) The acidic strength depends on the stability of the conjugate base formed after the loss of a proton $(H^+)$.$1$. $RCOOH$ (Carboxylic acid): The conjugate base $RCOO^-$ is stabilized by resonance between two equivalent oxygen atoms.$2$. $HOH$ (Water): The conjugate base is $OH^-$.$3$. $ROH$ (Alcohol): The conjugate base is $RO^-$. The electron-donating alkyl group ($+I$ effect) destabilizes the negative charge on oxygen,making alcohols less acidic than water.$4$. $HC \equiv CH$ (Terminal alkyne): The negative charge is on an $sp$ hybridized carbon,which is less electronegative than oxygen.Thus,the correct order is $RCOOH > HOH > ROH > HC \equiv CH$.

Which of the following is the correct order of acidic strength?

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