What is the correct order of reactivity for e | vedclass

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(D) The reactivity of benzene derivatives towards electrophilic substitution depends on the electron density of the ring. Electron-donating groups $(E

Vedclass · Accepted Answer

$C_6H_5NO_2 < C_6H_5Cl < C_6H_5CH_3 < C_6H_5NHCH_3$

Vedclass · Answer

(D) The reactivity of benzene derivatives towards electrophilic substitution depends on the electron density of the ring. Electron-donating groups $(EDG)$ increase reactivity,while electron-withdrawing groups $(EWG)$ decrease it.$1$. $-NHCH_3$ is a strong activating group (strong $+M$ effect).$2$. $-CH_3$ is a weakly activating group (hyperconjugation and $+I$ effect).$3$. $-Cl$ is a deactivating group ($-I$ effect dominates over $+M$ effect).$4$. $-CHO$ and $-NO_2$ are strongly deactivating groups ($-M$ and $-I$ effects).The order of reactivity is: $-NO_2$ (strongest $EWG$) Comparing the given options,option $D$ correctly represents the order: $C_6H_5NO_2 < C_6H_5Cl < C_6H_5CH_3 < C_6H_5NHCH_3$.

What is the correct order of reactivity for electrophilic substitution reactions for the following compounds?

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(Image)
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The reaction shown below is known as:
$2C_6H_5Cl + 2Na \xrightarrow{\text{dry ether}} C_6H_5-C_6H_5 + 2NaCl$

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