Match List-I with List-II and select the corr | vedclass

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Question

(A) The correct matches are as follows:$(I)$ Van Arkel method is used for the refining of metals like $Ti$ and $Zr$. Thus,$(I) - a$.$(II)$ Solvay proc

Vedclass · Accepted Answer

$I-a, II-b, III-d, IV-c$

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(A) The correct matches are as follows:$(I)$ Van Arkel method is used for the refining of metals like $Ti$ and $Zr$. Thus,$(I) - a$.$(II)$ Solvay process is the industrial process for the manufacture of sodium carbonate $(Na_2CO_3)$. Thus,$(II) - b$.$(III)$ Cupellation is a refining process used to separate noble metals like silver from base metals. Thus,$(III) - d$.$(IV)$ Poling is a process used for the refining of copper,where green wood poles are used to reduce copper oxide to copper. Thus,$(IV) - c$.Therefore,the correct sequence is $I-a, II-b, III-d, IV-c$.

List-$I$	List-$II$
$(I)$ Van Arkel method	$a.$ Refining of Titanium
$(II)$ Solvay process	$b.$ Manufacture of $Na_2CO_3$
$(III)$ Cupellation	$c.$ Refining of Copper
$(IV)$ Poling	$d.$ Refining of Silver

Match List-$I$ with List-$II$ and select the correct answer using the codes given below:

List-$I$ List-$II$

$(I)$ Van Arkel method $a.$ Refining of Titanium

$(II)$ Solvay process $b.$ Manufacture of $Na_2CO_3$

$(III)$ Cupellation $c.$ Refining of Copper

$(IV)$ Poling $d.$ Refining of Silver

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Match List-$I$ with List-$II$ and select the correct answer using the codes given below: List-$I$ List-$II$ $(I)$ Van Arkel method $a.$ Refining of Titanium $(II)$ Solvay process $b.$ Manufacture of $Na_2CO_3$ $(III)$ Cupellation $c.$ Refining of Copper $(IV)$ Poling $d.$ Refining of Silver