Easy
The principle of zone refining of metals is based on which of the following?
- APure metal has higher conductivity than impure metal.
- BImpure metal has a higher melting point than pure metal.
- CSolid metal has higher ideal characteristics than impurities.
- DImpurities are more soluble in the molten state than in the solid state.
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Similar Questions
Which among the following elements is obtained in pure form by the liquation process of refining?
The poling process is used for:
Easy
View SolutionMatch the following items of List-$I$ with those of List-$II$:
List-$I$ List-$II$ $(A)$ Nickel $(1)$ Electrolytic refining $(B)$ Titanium $(2)$ Zone refining $(C)$ Germanium $(3)$ van-Arkel method $(D)$ Copper $(4)$ Mond process
The correct answer is:
| List-$I$ | List-$II$ |
|---|---|
| $(A)$ Nickel | $(1)$ Electrolytic refining |
| $(B)$ Titanium | $(2)$ Zone refining |
| $(C)$ Germanium | $(3)$ van-Arkel method |
| $(D)$ Copper | $(4)$ Mond process |
The correct answer is:
Assertion : Lead,tin and bismuth are purified by liquation method.
Reason : Lead,tin and bismuth have low $m.p.$ as compared to impurities.
Reason : Lead,tin and bismuth have low $m.p.$ as compared to impurities.
MediumAIIMS 2010
View SolutionMatch the following List-$I$ (Method) with List-$II$ (Metal refined):
List-$I$ (Method) List-$II$ (Metal refined) $(A)$ Zone refining $(I)$ $Sn$ $(B)$ Liquation $(II)$ $In$ $(C)$ Vapour phase refining $(III)$ $Zn$ $(D)$ Distillation $(IV)$ $Zr$ - $(V)$ $Al$
The correct answer is:
| List-$I$ (Method) | List-$II$ (Metal refined) |
|---|---|
| $(A)$ Zone refining | $(I)$ $Sn$ |
| $(B)$ Liquation | $(II)$ $In$ |
| $(C)$ Vapour phase refining | $(III)$ $Zn$ |
| $(D)$ Distillation | $(IV)$ $Zr$ |
| - | $(V)$ $Al$ |
The correct answer is:
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