A hydrocarbon does not decolorize alkaline KM | vedclass

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Question

(A) $1$. Alkaline $KMnO_4$ (Baeyer's reagent) is used to test for unsaturation (alkenes and alkynes). It gets decolorized by compounds containing doub

Vedclass · Accepted Answer

Benzene

Vedclass · Answer

(A) $1$. Alkaline $KMnO_4$ (Baeyer's reagent) is used to test for unsaturation (alkenes and alkynes). It gets decolorized by compounds containing double or triple bonds.$2$. Ammoniacal silver nitrate (Tollens' reagent) reacts with terminal alkynes (alkynes with a hydrogen atom on the triple-bonded carbon) to form a white precipitate of silver acetylide.$3$. Benzene $(C_6H_6)$ is an aromatic hydrocarbon. It is stable and does not react with Baeyer's reagent under normal conditions,nor does it have acidic terminal hydrogen to react with Tollens' reagent.$4$. Acetylene $(C_2H_2)$,Propyne $(CH_3C\equiv CH)$,and But$-1-$yne $(CH_3CH_2C\equiv CH)$ are all terminal alkynes; they would decolorize $KMnO_4$ and react with ammoniacal silver nitrate.$5$. Therefore,the correct answer is Benzene.

$A$ hydrocarbon does not decolorize alkaline $KMnO_4$ solution and does not give a precipitate with ammoniacal silver nitrate. This hydrocarbon is .......

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