What is the decreasing order of acidic streng | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The acidity of hydrocarbons depends on the percentage of $s$-character in the $C-H$ bond.$1$. Ethyne $(CH \equiv CH)$ has $sp$ hybridization ($50\

Vedclass · Accepted Answer

$III > IV > II > I$

Vedclass · Answer

(C) The acidity of hydrocarbons depends on the percentage of $s$-character in the $C-H$ bond.$1$. Ethyne $(CH \equiv CH)$ has $sp$ hybridization ($50\% \ s$-character).$2$. Propyne $(CH_3-C \equiv CH)$ has an acidic terminal hydrogen attached to an $sp$ hybridized carbon.$3$. Ethene $(CH_2=CH_2)$ has $sp^2$ hybridization ($33.3\% \ s$-character).$4$. Ethane $(CH_3-CH_3)$ has $sp^3$ hybridization ($25\% \ s$-character).Comparing ethyne $(III)$ and propyne $(IV)$,the methyl group in propyne is electron-donating ($+I$ effect),which decreases the acidity of the terminal hydrogen compared to ethyne.Thus,the decreasing order of acidity is: $III > IV > II > I$.

What is the decreasing order of acidic strength for ethane $(I)$,ethene $(II)$,ethyne $(III)$,and propyne $(IV)$?

Similar Questions

In the following reactions,the product $S$ is

Reactant $(A)$ can be

The reaction is given by:
($1$-hydroxycyclopentane$-1,1-$dicarboxylic acid) $\xrightarrow[\Delta ]{K_2Cr_2O_7}\,(P)$
Product $(P)$ will be:

Which of the following hydrocarbons has the lowest dipole moment?

Compare the rate of catalytic hydrogenation using $H_2 / Pt$ for the following compounds $(a)$ and $(b)$:

Vedclass Test Series

Exam Paper Generator

Online Exam Module