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(A) The reaction of an alkane with chlorine in the presence of ultraviolet light is a free radical substitution reaction. To obtain only one monochlor

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Neopentane

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(A) The reaction of an alkane with chlorine in the presence of ultraviolet light is a free radical substitution reaction. To obtain only one monochloroalkane,all the hydrogen atoms in the alkane must be equivalent. In $Neopentane$ $(2,2-dimethylpropane)$,all $12$ hydrogen atoms are equivalent because the molecule is highly symmetrical. Therefore,substitution of any hydrogen atom by a chlorine atom results in the same product,$1-chloro-2,2-dimethylpropane$.

$A$ certain alkane is mixed with chlorine and irradiated with ultraviolet light. It yields only one monochloroalkane. Which alkane is it?

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