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Question

(A) The reactivity towards electrophilic aromatic substitution $(ESR)$ depends on the electron density in the benzene ring. Substituents that increase

Vedclass · Accepted Answer

$IV < I < II < III$

Vedclass · Answer

(A) The reactivity towards electrophilic aromatic substitution $(ESR)$ depends on the electron density in the benzene ring. Substituents that increase electron density (electron-donating groups) activate the ring,while those that decrease it (electron-withdrawing groups) deactivate the ring.$(I)$ Benzene: Reference compound.$(II)$ Toluene $(-CH_3)$: $-CH_3$ is an electron-donating group by $+I$ and hyperconjugation effects,activating the ring.$(III)$ Anisole $(-OCH_3)$: $-OCH_3$ is a strong electron-donating group by $+M$ effect,which strongly activates the ring.$(IV)$ Trifluoromethylbenzene $(-CF_3)$: $-CF_3$ is a strong electron-withdrawing group by $-I$ effect,which strongly deactivates the ring.Order of activation: $-CF_3$ (deactivating) Therefore,the increasing order of reactivity is $IV < I < II < III$.

Arrange the following compounds in increasing order of their reactivity towards electrophilic substitution:

Similar Questions

The correct arrangement for the decreasing order of electrophilic substitution for the above compounds is:

The order of reactivity of the following compounds towards electrophilic substitution will be - [where $\phi = C_6H_5$]:
$I. \phi-CH_3$
$II. \phi-CH_2-CH_3$
$III. \phi-CH(CH_3)_2$
$IV. \phi-C(CH_3)_3$

The correct order of reactivity in electrophilic substitution reaction of the following compounds is:

Calculate the total number of $\sigma$ bonds in toluene $(C_6H_5CH_3)$.

Which of the following compounds is most reactive towards electrophilic nitration?

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