In the bromination of isobutane,the relative | vedclass

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(C) The substrate is isobutane,which has $9$ equivalent $1^o$ hydrogens and $1$ $3^o$ hydrogen.Relative rate for $3^o$ product $(a)$: $1 	imes 1600 =

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$99.4\%, 0.6\%$

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(C) The substrate is isobutane,which has $9$ equivalent $1^o$ hydrogens and $1$ $3^o$ hydrogen.Relative rate for $3^o$ product $(a)$: $1 	imes 1600 = 1600$.Relative rate for $1^o$ product $(b)$: $9 	imes 1 = 9$.Total relative rate = $1600 + 9 = 1609$.Percentage of product $(a) = (1600 / 1609) 	imes 100 \approx 99.4\%$.Percentage of product $(b) = (9 / 1609) 	imes 100 \approx 0.6\%$.Thus,the yields are $99.4\%$ and $0.6\%$ respectively.

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