$CH_2 = CH_2 \xrightarrow[KOH/H_2O]{KMnO_4} X = ......$

$17 \, mg$ of a hydrocarbon ($M$.$F$. $C_{10}H_{16}$) takes up $8.40 \, mL$ of $H_2$ gas measured at $0^{\circ}C$ and $760 \, mm$ of $Hg$. Ozonolysis of the same hydrocarbon yields acetone,formaldehyde,and a compound with the structure $CH_3-CO-CH_2-CH_2-CHO$. The number of double bonds present in the hydrocarbon is $...........$.

The reaction $R-CH=CH_2 \xrightarrow{Na/NH_3, C_2H_5OH} R-CH_2CH_3$ is known as:

$(CH_3)_3CH$ $\xrightarrow{KMnO_4} X$ $\xrightarrow[573 \ K]{Cu} Y$
The number of $sp^3$ and $sp^2$ carbons in $Y$ are respectively

Identify the type of the given reactions:
$(a) \ CH_3CH_2OH \xrightarrow[\Delta]{\text{Conc. } H_2SO_4} CH_2 = CH_2 + H_2O$
$(b) \ CH_2BrCH_2Br + Zn \xrightarrow{\Delta} CH_2 = CH_2 + ZnBr_2$
$(c) \ CH_3CHBr - CH_2Br + Zn \xrightarrow{\Delta} CH_3CH = CH_2 + ZnBr_2$
$(d) \ RC \equiv CR' + H_2 \xrightarrow{Na, \text{liquid } NH_3} RCH = CHR'$
$(e) \ CH_3CH_2Cl + KOH \xrightarrow{\text{ethanol, } KOH} CH_2 = CH_2 + KCl + H_2O$

The addition of $HI$ to the double bond of propene yields isopropyl iodide and not $n$-propyl iodide because the addition proceeds through the formation of: