In Friedel-Crafts alkylation,the other suitab | vedclass

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Question

(A) Friedel-Crafts alkylation involves the reaction of an aromatic hydrocarbon (like benzene) with an alkyl halide in the presence of a Lewis acid cat

Vedclass · Accepted Answer

$C_6H_6 + CH_3Cl$

Vedclass · Answer

(A) Friedel-Crafts alkylation involves the reaction of an aromatic hydrocarbon (like benzene) with an alkyl halide in the presence of a Lewis acid catalyst such as $AlCl_3$.In the given options,$C_6H_6 + CH_3Cl$ represents the reaction between benzene and methyl chloride,which is a classic example of Friedel-Crafts alkylation.$C_6H_6 + CH_3COCl$ represents Friedel-Crafts acylation,not alkylation.Therefore,the correct option is $A$.

In Friedel-Crafts alkylation,the other suitable substance used with $AlCl_3$ is..........

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