What is the product formed when CH_3-CH=CHBr | vedclass

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(B) The reaction of an alkene with $HBr$ in the presence of peroxide follows the anti-Markovnikov addition rule (Kharasch effect or peroxide effect).I

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$CH_3-CH(Br)-CH_2Br$

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(B) The reaction of an alkene with $HBr$ in the presence of peroxide follows the anti-Markovnikov addition rule (Kharasch effect or peroxide effect).In $CH_3-CH=CHBr$,the double bond is between $C_2$ and $C_3$.According to the anti-Markovnikov rule,the $Br^-$ atom attaches to the carbon atom of the double bond that has more hydrogen atoms.Here,$CH_3-CH=CHBr$ is an unsymmetrical alkene.However,the presence of the $Br$ group on the terminal carbon influences the electron density.Applying the anti-Markovnikov rule,$H$ adds to the carbon with fewer hydrogens and $Br$ adds to the carbon with more hydrogens.Thus,$CH_3-CH=CHBr + HBr \xrightarrow{	ext{peroxide}} CH_3-CH(Br)-CH_2Br$.

What is the product formed when $CH_3-CH=CHBr$ reacts with $HBr$ in the presence of peroxide?

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