The number of chiral carbons in beta-D-(+)-gl | vedclass

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(C) The structure of $\beta-D-(+)$-glucose is a cyclic hemiacetal form of glucose.In the cyclic structure,the carbon atoms at positions $C_1, C_2, C_3

Vedclass · Accepted Answer

$5$

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(C) The structure of $\beta-D-(+)$-glucose is a cyclic hemiacetal form of glucose.In the cyclic structure,the carbon atoms at positions $C_1, C_2, C_3, C_4,$ and $C_5$ are chiral centers.$C_1$ is the anomeric carbon,which is bonded to $-H, -OH, -O-$ (ring oxygen),and $-C_2$.$C_2, C_3,$ and $C_4$ are bonded to four different groups.$C_5$ is bonded to $-H, -CH_2OH, -O-$ (ring oxygen),and $-C_4$.Therefore,there are $5$ chiral carbon atoms in $\beta-D-(+)$-glucose.

The number of chiral carbons in $\beta-D-(+)$-glucose is ......

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