Dispersed colloidal iron (III) hydroxide and | vedclass

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(C) $1$. Iron $(III)$ hydroxide sol is positively charged,and gold sol is negatively charged. $2$. According to the Hardy-Schulze rule,the coagulating

Vedclass · Accepted Answer

Mixing the sols has no effect.

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(C) $1$. Iron $(III)$ hydroxide sol is positively charged,and gold sol is negatively charged. $2$. According to the Hardy-Schulze rule,the coagulating power of an electrolyte depends on the valency of the ion carrying a charge opposite to that of the colloidal particle. $3$. For negatively charged gold sol,$Mg^{2+}$ ions (from $MgCl_2$) are more effective than $Cl^-$ ions. For positively charged iron $(III)$ hydroxide sol,$SO_4^{2-}$ ions (from $Na_2SO_4$) are more effective. $4$. Option $A$ is incorrect because $MgCl_2$ (providing $Mg^{2+}$) is more effective for the negatively charged gold sol,but the statement implies a comparison that is not standard. However,option $C$ is definitely incorrect because mixing oppositely charged sols leads to mutual coagulation. Thus,the statement 'Mixing the sols has no effect' is false.

Dispersed colloidal iron $(III)$ hydroxide and colloidal gold are positively and negatively charged,respectively. Which of the following statements is $NOT$ correct?

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