Which of the following electrolytes is the mo | vedclass

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(C) The $Sb_2S_3$ sol is a negatively charged sol. According to the Hardy-Schulze rule,the coagulating power of an electrolyte increases with the incr

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$Al_2(SO_4)_3$

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(C) The $Sb_2S_3$ sol is a negatively charged sol. According to the Hardy-Schulze rule,the coagulating power of an electrolyte increases with the increase in the valency of the coagulating ion (the ion with a charge opposite to that of the sol). Since $Sb_2S_3$ is negatively charged,the positive ions are responsible for coagulation. The valencies of the positive ions are: $Na^+$ $(+1)$,$Ca^{2+}$ $(+2)$,$Al^{3+}$ $(+3)$,and $NH_4^+$ $(+1)$. Since $Al^{3+}$ has the highest valency $(+3)$,$Al_2(SO_4)_3$ is the most effective coagulating agent.

Which of the following electrolytes is the most effective coagulating agent for $Sb_2S_3$ sol among $Na_2SO_4$,$CaCl_2$,$Al_2(SO_4)_3$,and $NH_4Cl$?

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