Phenol reacts with CHCl_3 and NaOH at 340 K | vedclass

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Question

(B) The reaction of phenol with chloroform $(CHCl_3)$ in the presence of aqueous sodium hydroxide $(NaOH)$ at $340 \ K$ is known as the Reimer-Tiemann

Vedclass · Accepted Answer

Salicylaldehyde

Vedclass · Answer

(B) The reaction of phenol with chloroform $(CHCl_3)$ in the presence of aqueous sodium hydroxide $(NaOH)$ at $340 \ K$ is known as the Reimer-Tiemann reaction. This reaction introduces an aldehyde group $(-CHO)$ at the ortho position of the phenol ring,resulting in the formation of salicylaldehyde ($2$-hydroxybenzaldehyde). The chemical equation is: $C_6H_5OH + CHCl_3 + 3NaOH \rightarrow C_6H_4(OH)(CHO) + 3NaCl + 2H_2O$.

Phenol reacts with $CHCl_3$ and $NaOH$ at $340 \ K$ to give .......

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