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(C) The debromination of $meso-2,3-dibromobutane$ occurs via an $E2$ elimination mechanism using zinc dust in ethanol.In the $meso$ isomer,the two bro

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$cis-2-butene$

Vedclass · Answer

(C) The debromination of $meso-2,3-dibromobutane$ occurs via an $E2$ elimination mechanism using zinc dust in ethanol.In the $meso$ isomer,the two bromine atoms are in an anti-periplanar conformation when the molecule is in its eclipsed or gauche-like state,but specifically,the $meso$ form allows for the anti-elimination of the two bromine atoms to yield the $cis-2-butene$ isomer.Therefore,the major product is $cis-2-butene$.

What is the major product formed during the debromination of $meso-2,3-dibromobutane$?

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