Identify the correct order of stability for carbocations.

  • A
    $CH_3^+ > 1^o C^+ > 2^o C^+ > 3^o C^+$
  • B
    $3^o C^+ > 2^o C^+ > 1^o C^+ > CH_3^+$
  • C
    $2^o C^+ > 1^o C^+ > CH_3^+ > 3^o C^+$
  • D
    $1^o C^+ > CH_3^+ > 2^o C^+ > 3^o C^+$

Explore More

Similar Questions

The correct order of increasing stabilities of the following carbocations is:
$(i)$ Allyl carbocation
$(ii)$ Ethyl carbocation
$(iii)$ Benzyl carbocation
$(iv)$ Isobutyl carbocation

Which of the following is an incorrect stability order?

Among the following carbocations:
$(I)$ $Ph_{2}\stackrel{+}{C} CH_{2} Me$
$(II)$ $Ph CH_{2} CH_{2} \stackrel{+}{C} HPh$
$(III)$ $Ph_{2} CH \stackrel{+}{C} HMe$
$(IV)$ $Ph_{2} C(Me) \stackrel{+}{C} H_{2}$
The order of stability is:

The decreasing order of hydride affinity for the following carbocations is:
$A: CH_2=CH-C^+(CH_3)_2$
$B: (C_6H_5)_3C^+$
$C: (CH_3)_3C^+$
$D: (Cyclopropyl)_3C^+$
Choose the correct answer from the options given below:

In which of the following pairs is $A$ more stable than $B$?
$A$ $B$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo