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(B) The free radical chlorination of ethane $(C_2H_6)$ is a chain reaction that proceeds through multiple steps,often leading to poly-chlorinated prod

Vedclass · Accepted Answer

$C_2H_6 (	ext{excess}) + Cl_2 \xrightarrow{hv} C_2H_5Cl + HCl$

Vedclass · Answer

(B) The free radical chlorination of ethane $(C_2H_6)$ is a chain reaction that proceeds through multiple steps,often leading to poly-chlorinated products like $C_2H_4Cl_2$,$C_2H_3Cl_3$,etc.To maximize the yield of the mono-substituted product $(C_2H_5Cl)$,it is necessary to use an excess of the alkane $(C_2H_6)$.By using an excess of $C_2H_6$,the probability of a chlorine radical colliding with an ethane molecule is significantly higher than colliding with an already formed $C_2H_5Cl$ molecule.Therefore,option $B$ provides the correct condition for the maximum yield of $C_2H_5Cl$.

Which of the following conditions will give the maximum yield of $C_2H_5Cl$?

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