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(D) The compound '$X$' has three carbon atoms and reacts with aqueous $KOH$ to form an aldehyde. This indicates that '$X$' is a geminal dihalide at th

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$1,1$-dichloropropane

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(D) The compound '$X$' has three carbon atoms and reacts with aqueous $KOH$ to form an aldehyde. This indicates that '$X$' is a geminal dihalide at the terminal position,specifically $1,1$-dichloropropane $(CH_3CH_2CHCl_2)$.Reaction with aqueous $KOH$: $CH_3CH_2CHCl_2 + 2KOH(aq) \rightarrow CH_3CH_2CHO + 2KCl + H_2O$.Reaction with alcoholic $KOH$: $CH_3CH_2CHCl_2 + 2KOH(alc) \rightarrow CH_3C \equiv CH + 2KCl + 2H_2O$.The product $CH_3C \equiv CH$ (propyne) is a terminal alkyne,which reacts with ammoniacal $Cu_2Cl_2$ to form a red precipitate of copper$(I)$ propynide $(CH_3C \equiv CCu)$.

$A$ dihalogen derivative '$X$' of a hydrocarbon with three carbon atoms reacts with alcoholic $KOH$ to give another hydrocarbon which forms a red precipitate with ammoniacal $Cu_2Cl_2$. '$X$' gives an aldehyde upon reaction with aqueous $KOH$. What is the compound '$X$'?

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