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(B) The reaction of alcohols with halogen acids proceeds via the formation of a carbocation intermediate.The reactivity of alcohols towards halogen ac

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$(3) > (2) > (1)$

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(B) The reaction of alcohols with halogen acids proceeds via the formation of a carbocation intermediate.The reactivity of alcohols towards halogen acids follows the order: $3^\circ > 2^\circ > 1^\circ$ alcohol.This is because the stability of the carbocation formed is $3^\circ > 2^\circ > 1^\circ$.$(1)$ is a primary $(1^\circ)$ alcohol: $CH_3CH_2CH_2OH$.$(2)$ is a secondary $(2^\circ)$ alcohol: $CH_3CH_2CH(CH_3)OH$.$(3)$ is a tertiary $(3^\circ)$ alcohol: $CH_3CH_2C(CH_3)_2OH$.Therefore,the order of reactivity is $(3) > (2) > (1)$.

What is the order of reactivity of the following alcohols with halogen acids?
$(1) \ CH_3CH_2CH_2OH$
$(2) \ CH_3CH_2CH(CH_3)OH$
$(3) \ CH_3CH_2C(CH_3)_2OH$

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What is the order of reactivity of the following alcohols with halogen acids?$(1) \ CH_3CH_2CH_2OH$$(2) \ CH_3CH_2CH(CH_3)OH$$(3) \ CH_3CH_2C(CH_3)_2OH$