What is the major product obtained when dieth | vedclass

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(C) The reaction of diethyl ether $(C_2H_5-O-C_2H_5)$ with concentrated $HI$ at $0^o C$ proceeds via the protonation of the ether oxygen atom.Step $1$

Vedclass · Accepted Answer

Both $C_2H_5OH$ and $C_2H_5I$

Vedclass · Answer

(C) The reaction of diethyl ether $(C_2H_5-O-C_2H_5)$ with concentrated $HI$ at $0^o C$ proceeds via the protonation of the ether oxygen atom.Step $1$: Protonation of ether: $C_2H_5-O-C_2H_5 + HI \rightarrow C_2H_5-O^+(H)-C_2H_5 + I^-$.Step $2$: Nucleophilic attack by $I^-$ on one of the ethyl groups: $I^- + C_2H_5-O^+(H)-C_2H_5 \rightarrow C_2H_5I + C_2H_5OH$.Since both alkyl groups are identical,the reaction produces one molecule of ethyl iodide $(C_2H_5I)$ and one molecule of ethanol $(C_2H_5OH)$.Therefore,both products are formed.

What is the major product obtained when diethyl ether reacts with concentrated $HI$ at $0^o C$?

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