What is the stoichiometric ratio of the produ | vedclass

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Question

(A) The balanced chemical equation for the disproportionation of potassium manganate in acidic medium is: $3K_2MnO_4 + 2H_2SO_4 \rightarrow 2KMnO_4 +

Vedclass · Accepted Answer

$2 : 2 : 1 : 2$

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(A) The balanced chemical equation for the disproportionation of potassium manganate in acidic medium is: $3K_2MnO_4 + 2H_2SO_4 \rightarrow 2KMnO_4 + 2K_2SO_4 + MnO_2 + 2H_2O$. In this reaction,the products are $KMnO_4$,$K_2SO_4$,$MnO_2$,and $H_2O$. The stoichiometric coefficients of the products are $2$,$2$,$1$,and $2$ respectively. However,looking at the provided options and the standard representation of this reaction,the ratio of the products $(KMnO_4 : K_2SO_4 : MnO_2 : H_2O)$ is $2 : 2 : 1 : 2$.

What is the stoichiometric ratio of the products in the reaction: $3K_2MnO_4 + 2H_2SO_4 \rightarrow 2KMnO_4 + 2K_2SO_4 + MnO_2 + 2H_2O$?

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