If the magnetic moment (mu) of an oxide of ma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The formula for magnetic moment is $\mu = \sqrt{n(n+2)}$,where $n$ is the number of unpaired electrons.Given $\mu = 4.9 \ BM$,we have $\sqrt{n(n+2

Vedclass · Accepted Answer

$Mn_2O_3$

Vedclass · Answer

(B) The formula for magnetic moment is $\mu = \sqrt{n(n+2)}$,where $n$ is the number of unpaired electrons.Given $\mu = 4.9 \ BM$,we have $\sqrt{n(n+2)} = 4.9$.Squaring both sides,$n(n+2) \approx 24$,which gives $n = 4$.In $Mn_2O_3$,the oxidation state of $Mn$ is $+3$.The electronic configuration of $Mn^{3+}$ is $[Ar] \ 3d^4$.Since there are $4$ unpaired electrons,the magnetic moment is $\sqrt{4(4+2)} = \sqrt{24} \approx 4.9 \ BM$.Therefore,the oxide is $Mn_2O_3$.

If the magnetic moment $(\mu)$ of an oxide of manganese is $4.9 \ BM$,which oxide is it?

Similar Questions

The formula of corrosive sublimate is

Among $Co^{3+}$,$Ti^{2+}$,$V^{2+}$ and $Cr^{2+}$ ions,one if used as a reagent cannot liberate $H_{2}$ from dilute mineral acid solution,its spin-only magnetic moment in gaseous state is $.....$ $B.M.$ (Nearest integer)

What are interstitial compounds? Give their examples and characteristics.

Corundum is

Write two uses of $KMnO_4$ and $K_2Cr_2O_7$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module