(i) La(OH)_3 is the least basic among lanthan | vedclass

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(B) Statement $(i)$ is incorrect because $La(OH)_3$ is the most basic lanthanide hydroxide due to the largest ionic radius of $La^{3+}$. As we move fr

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$(ii)$ and $(iii)$

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(B) Statement $(i)$ is incorrect because $La(OH)_3$ is the most basic lanthanide hydroxide due to the largest ionic radius of $La^{3+}$. As we move from $La$ to $Lu$,the ionic radius decreases,leading to a decrease in basicity.Statement $(ii)$ is correct because $Zr^{4+}$ and $Hf^{4+}$ have almost identical ionic radii due to lanthanoid contraction.Statement $(iii)$ is correct because $Ce^{4+}$ has a strong tendency to gain an electron to form the stable $Ce^{3+}$ $(4f^1)$ configuration,thus acting as a strong oxidizing agent.Therefore,statements $(ii)$ and $(iii)$ are correct.

$(i) La(OH)_3$ is the least basic among lanthanide hydroxides. $(ii) Zr^{4+}$ and $Hf^{4+}$ have almost identical ionic radii. $(iii) Ce^{4+}$ can act as an oxidizing agent. Which of the above statements are correct?

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