Which lanthanoid element exhibits +2 and +3 o | vedclass

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Question

(D) The lanthanoids generally exhibit a $+3$ oxidation state. However,some elements show $+2$ or $+4$ oxidation states due to stable electronic config

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$Eu$

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(D) The lanthanoids generally exhibit a $+3$ oxidation state. However,some elements show $+2$ or $+4$ oxidation states due to stable electronic configurations (like half-filled or fully-filled $f$-orbitals). Europium ($Eu$,atomic number $63$) has the electronic configuration $[Xe] 4f^7 6s^2$. It loses two electrons from the $6s$ orbital to form $Eu^{2+}$ $(4f^7)$,which is a stable half-filled configuration. It can also lose one more electron to form $Eu^{3+}$ $(4f^6)$. Therefore,$Eu$ exhibits both $+2$ and $+3$ oxidation states.

Which lanthanoid element exhibits $+2$ and $+3$ oxidation states?

Similar Questions

Among $Ce(4f^{1} 5d^{1} 6s^{2})$,$Nd(4f^{3} 6s^{2})$,$Eu(4f^{7} 6s^{2})$ and $Dy(4f^{10} 6s^{2})$,the elements having highest and lowest $3^{rd}$ ionisation energies,respectively are

From the list given below,the number of lanthanides which exhibit $+4$ oxidation state in their oxides is: $Pr, Nd, Pm, Sm, Eu, Gd, Tb, Dy$

Observe the following $f$-block elements: $Eu (Z=63)$; $Pu (Z=94)$; $Cf (Z=98)$; $Sm (Z=62)$; $Gd (Z=64)$; $Cm (Z=96)$. How many of the above have half-filled $f$-orbitals in their ground state?

$Ce - 58$ is a member of

Which of the following ions is the strongest oxidizing agent? [ Atomic Number of $Ce = 58, Eu = 63, Tb = 65, Lu = 71$ ]

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