Which of the following represents the correct order of density for the given $3d$ series elements?

  • A
    $Cu > Ni > Zn > Sc$
  • B
    $Ni > Cu > Zn > Sc$
  • C
    $Zn > Cu > Ni > Sc$
  • D
    $Sc > Zn > Ni > Cu$

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Similar Questions

Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A)$: The first ionization enthalpy of $3d$ series elements is more than that of group $2$ metals.
Reason $(R)$: In $3d$ series of elements,successive filling of $d$-orbitals takes place.
In the light of the above statements,choose the correct answer from the options given below:

$A$ transition metal $M$ among $Sc, Ti, V, Cr, Mn$ and $Fe$ has the highest second ionisation enthalpy. The spin only magnetic moment value of $M^{+}$ ion is $. . . . . . . BM$ (Near integer)
(Given atomic number $Sc: 21, Ti: 22, V: 23, Cr: 24, Mn: 25, Fe: 26$)

Which of the following is more paramagnetic?

Match the following:
$I. \ Zn^{2+}$$(i) \ d^8 \ \text{configuration}$
$II. \ Cu^{2+}$$(ii) \ \text{Colourless}$
$III. \ Ni^{2+}$$(iii) \ \mu = 1.73 \ \text{BM}$

The correct order of spin-only magnetic moment (in $BM$) for $Mn^{2+}$,$Cr^{2+}$,and $Ti^{2+}$ ions is:

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