Toluene is nitrated,and the resulting product | vedclass

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(D) $1$. Nitration of toluene $(C_6H_5CH_3)$ gives a mixture of $o$-nitrotoluene and $p$-nitrotoluene.$2$. Reduction of these nitro compounds using $S

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$O$ and $P$ bromotoluene

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(D) $1$. Nitration of toluene $(C_6H_5CH_3)$ gives a mixture of $o$-nitrotoluene and $p$-nitrotoluene.$2$. Reduction of these nitro compounds using $Sn/HCl$ or $Fe/HCl$ yields $o$-toluidine and $p$-toluidine ($o$-methylaniline and $p$-methylaniline).$3$. Diazotization of these amines with $NaNO_2/HCl$ at $0-5 \ ^\circ C$ produces the corresponding diazonium salts ($o$-methylbenzenediazonium chloride and $p$-methylbenzenediazonium chloride).$4$. Heating these diazonium salts with cuprous bromide $(CuBr/HBr)$ (Sandmeyer reaction) replaces the diazonium group with a bromine atom,resulting in $o$-bromotoluene and $p$-bromotoluene.

Toluene is nitrated,and the resulting product is reduced. This is then diazotized and heated with cuprous bromide. What are the final products?

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